Larmor Equation - QM Derivation
The direct relationship between the magnetic moment (μ) and the spin angular momentum vector (S) is quantized thus:
μ = γS = γhms
where γ is the gyromagnetic ratio, ms is the azimuthal spin quantum number (ms = ±½ for 1H) and h is the Planck constant over 2π. The formula for the energy E associated with a magnetic moment μ in an external magnetic field B is
E = -μ · B (the dot product)
Thus, discrete energy levels may be defined by
E = -γhmsB0 (the cosθ term of the dot product = ±1 since the values of ms correspond to spin polarisation with and against the field; θ is 0° or 180°).
This equation corresponds to the Zeeman energy eigenstates. The quantum of energy which can be absorbed or released by the spin system is, therefore,
ΔE = Ehigher - Elower
= E(ms=-½) - E(ms=+½)
= ½γhB0 - (-½γhB0)
= γhB0
for a constant field B=B0. According to the de Broglie relation E=hω we may write
ΔE = γhB0 = hω0
from which the Larmor equation results:
ω0 = γB0.
Further reading on this topic:
Books: MRI: Physical Principles & Sequence Design p71, MRI From Picture to Proton p138